GCE ORDINARY LEVEL 2013

Why cant we use algebraic moethd?Let x be the number of coinsTHe first man leaves 2/3 (x-1)= (2x-2)/3The second man leaves( 4x-10)/9Third man leaves = (8x-38)/27When all come together they saw( 8x-38)/27 coins After putting one in the box they have(8x-65)/27Clearly this is a multiple of 3(8x-65)/27 = k*3x= (81k+65)/8we get smallest x satisfying this condition is by choosing k = 7When k = 7 we get x = 79

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